Elektronika | Felsőoktatás » Elektronikai alapismeretek angol nyelven középszintű írásbeli érettségi vizsga megoldással, 2012

ÉRETTSÉGI VIZSGA 2012. május 25 Név: . osztály: ELEKTRONIKAI ALAPISMERETEK ANGOL NYELVEN KÖZÉPSZINTŰ ÍRÁSBELI VIZSGA 2012. május 25 8:00 Az írásbeli vizsga időtartama: 180 perc Pótlapok száma Tisztázati Piszkozati NEMZETI ERŐFORRÁS MINISZTÉRIUM Elektronikai alapismeretek angol nyelven középszint írásbeli vizsga 1212 Elektronikai alapismeretek angol nyelven középszint Név: . osztály: Important information You may use only a pocket calculator that cannot store or display texts, drawing tools, templates, and rulers as auxiliary tools for solving this written test. Use a blue-ink pen for writing and a black lead pencil for drawing. For solving simple short questions, use the free space below each question in the exam sheet. For solving complex questions, use supplementary sheets to be distributed by supervising teachers, by specifying your name and class on them. Attach a page number to each supplementary sheet When solving questions requiring

calculations, take care to write down relationships (formulas) correctly, make substitutions properly, and do calculations accurately. If you fail on any of those, points will be deducted from your score. Maximum points for an end-result will only be given to you when its amount and measurement unit are both fully correct. When solving questions, take care to produce a neat and well-organised written test, to use standard symbols, and to meet requirements in terms of engineering, format, and aesthetics. Points will be deducted for the lack of any of them. Cross erroneous parts, if any, by a diagonal line. Within the duration of the examination, you may prepare a fair copy too. In that case you will prepare a “Draft” copy and a “Fair” copy by using continuous page numbering. írásbeli vizsga 1212 2/8 2012. május 25 Elektronikai alapismeretek angol nyelven középszint Név: . osztály: Simple, short questions Maximum points: 40 1.) Complete the table based on the

sample provided in the first column 15 mA 120μH 5 TΩ 25μS (3 points) 47 nF 1.5 ⋅ 10 −2 A 2.) Determine the resultant resistance of three resistors connected in parallel Data: R1 = 10 kΩ, R2 = 15 kΩ, R3 = 30 kΩ (3 points) R= 3.) Determine the value of the series resistor required to extend the measurement limit of a basic instrument from U0 = 0.2 V to U = 75 V I0 = 200 µA flows through the basic instrument when it is subjected to U0 = 0.2 V (3 points) Rr = 4.) Complete the table below The table must express the inductive reactance as a function of frequency. (3 points) f (kHz) 1 XL (Ω) 2 3 4 500 5.) Determine the supply voltage of an RL series circuit Data: I = 2 mA, R = 2 kΩ, XL = 1.5 kΩ (4 points) U= 6.) Determine the impedance of an RC parallel circuit Data: U = 6 V, IR = 10 mA, IC = 7.5 mA (4 points) Z= 7.) Determine the voltage amplification values in decibels in the table below (3 points) Au 1 80 2 0.5 au (dB) írásbeli vizsga 1212

3/8 2012. május 25 Elektronikai alapismeretek angol nyelven középszint Név: . osztály: 8.) Calculate the output voltage of an amplifier loaded with a load resistor of Rl = 75 kΩ The amplifier, when unloaded, has an output resistance of Rout = 2.5 kΩ and an output voltage of Uout0 = 800 mV. (3 points) U out = 9.) Determine the voltage amplification of a basic common-source amplifier circuit Data: y21S = 5 mS, y22S = 25 µS, RD = 5 kΩ, Rl = 7.5 kΩ (4 points) Aul = 10.) Draw a basic common-collector amplifier circuit Parts: 1 NPN transistor, 3 resistors, 2 electrolytic capacitors. (4 points) 11.) Write down the conjunctive serial number form of the logic function below ‘A’ is used to denote the variable of the highest place value. (3 points) ( )( )( F4 = A + B + C + D ⋅ A + B + C + D ⋅ A + B + C + D ) F4 = 12.) Write down the disjunctive normal form of the logic function below (3 points) F = A ⋅B⋅C + B⋅C⋅D + A ⋅B⋅C⋅D 4 F4 = írásbeli

vizsga 1212 4/8 2012. május 25 Elektronikai alapismeretek angol nyelven középszint Név: . osztály: Complex questions Maximum points: 60 Question 1 Maximum points: 15 Calculate a DC network C1 C2 R U C3 C4 C5 Data: U = 15 V R = 100 kΩ C2 = 20 µF C4 = 20 µF C1 = 10 µF C3 = 10 µF C5 = 30 µF Tasks: a) Determine the resultant capacitance (C) of the capacitor network C1, C2, C3, C4, C5. b) Determine the resultant charge (Q) and the voltage appearing across each capacitor (U1, U2, U3, U4, U5). c) After the removal of the generator, the capacitor network is discharged through resistor R. Determine the time factor (τ) of the discharge Question 2 Maximum points: 15 Calculate an AC circuit I L R C Data: U=6V XL = 2.5 kΩ XC = 4 kΩ U f = 5 kHz R = 2 kΩ Tasks: a) Determine the impedance of the circuit and the current through it (Z, I). b) Determine the voltage appearing across each element in the circuit (UR, UC, UL). c) Determine the values of the

inductor and the capacitor (L, C). írásbeli vizsga 1212 5/8 2012. május 25 Elektronikai alapismeretek angol nyelven középszint Név: . osztály: Question 3 Maximum points: 15 Calculate a low frequency amplifier Rg In C1 IC R3 R1 Uin Ug C2 Out Uout Rt R2 Data: Au = 10 C2 = 10 µF R1 = 27 kΩ Rt = 2 kΩ R2 = 30 kΩ Ug = 500 mV Rg = 5 kΩ The operational amplifier may be considered to be ideal for the purposes of the calculation. The capacitive reactance of the capacitors is negligible in tasks a), b), and c). Tasks: a) Determine the input resistance of the amplifier (Rin). b) Determine the value of resistor R3. c) Calculate the input- and output voltage of the amplifier (Uin, Uout), and its output power (Pout). d) Determine the limit frequency (fl) of the output coupling component (C2-Rt). Question 4 Maximum points: 15 Design a combinational circuit The Veitch-table of a conjunctive logic function is given as follows: C A 1 1 1 1 1 1 1 1 B 1

D 1 B D Tasks: a) Write down the serial number form of the conjunctive function. ’A’ is used to denote the variable of the highest place value. b) Simplify the function through the graphical method. c) Realize the function by using NOT, AND and OR gates. (The variables are available in original form only.) d) Realize the function by using NOR gates. (The variables are available in original form only.) írásbeli vizsga 1212 6/8 2012. május 25 Elektronikai alapismeretek angol nyelven középszint írásbeli vizsga 1212 Név: . osztály: 7/8 2012. május 25 Elektronikai alapismeretek angol nyelven középszint topic Név: . osztály: Maximum Achieved Maximum Achieved points for points for points points topic topic 3 3 3 3 4 4 40 3 3 4 4 3 3 15 15 60 15 serial number of question 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 1. 2. 3. Simple, short questions Complex questions 4. 15 Score of the written part of the examination 100 correcting teacher Date: .

pontszáma egész számra kerekítve/ achieved points rounded up to the next integer programba beírt egész pontszám/ integer score captured in computer program Egyszerű, rövid feladatok/ Simple short questions Összetett feladatok/ Complex questions javító tanár / correcting teacher Dátum/Date: . írásbeli vizsga 1212 jegyző / notary Dátum/Date: . 8/8 2012. május 25 ÉRETTSÉGI VIZSGA 2012. május 25 Elektronikai alapismeretek angol nyelven középszint Javítási-értékelési útmutató 1212 ELEKTRONIKAI ALAPISMERETEK ANGOL NYELVEN KÖZÉPSZINTŰ ÍRÁSBELI ÉRETTSÉGI VIZSGA JAVÍTÁSI-ÉRTÉKELÉSI ÚTMUTATÓ NEMZETI ERŐFORRÁS MINISZTÉRIUM Elektronikai alapismeretek angol nyelven középszint Javítási-értékelési útmutató Simple, short questions Maximum points: 40 1.) Complete the table based on the sample provided in the first column 15 mA 120μH 5 TΩ 25μS

47 nF 1.5 ⋅10 −2 A 1.2 ⋅ 10 −4 H 5 ⋅ 1012 Ω 2.5 ⋅ 10 −5 S 4.7 ⋅ 10 −8 F 3 points 2.) Determine the resultant resistance of three resistors connected in parallel Data: R1 = 10 kΩ, R2 = 15 kΩ, R3 = 30 kΩ R = R 1 × R 2 × R 3 = 10 kΩ × 15 kΩ × 30 kΩ = 5 kΩ 3 points 3.) Determine the value of the series resistor required to extend the measurement limit of a basic instrument from U0 = 0.2 V to U = 75 V I0 = 200 µA flows through the basic instrument when it is subjected to U0 = 0.2 V Rr = U − U 0 7.5V − 02V = = 36.5 kΩ I0 2 ⋅10 −4 A 3 points 4.) Complete the table below The table must express the inductive reactance as a function of frequency. f (kHz) 1 2 3 4 XL (Ω) 250 500 750 1000 3 points 5.) Determine the supply voltage of an RL series circuit Data: I = 2 mA, R = 2 kΩ, XL = 1.5 kΩ U = I ⋅ R 2 + X L2 = 2 ⋅10 −3 A ⋅ (2 ⋅10 Ω) + (1.5 ⋅10 Ω) 2 3 2 3 = 5V 4 points 6.) Determine the impedance of an RC

parallel circuit Data: U = 6 V, IR = 10 mA, IC = 7.5 mA Z= U I R2 + I C2 = 6V = 480 Ω (10 mA)2 + (7.5 mA)2 4 points 7.) Determine the voltage amplification values in decibels in the table below Au 1 80 2 0.5 au (dB) 0 38.06 3 − 6.02 írásbeli vizsga 1212 2/8 3 points 2012. május 25 Elektronikai alapismeretek angol nyelven középszint Javítási-értékelési útmutató 8.) Calculate the output voltage of an amplifier loaded with a load resistor of Rl = 75 kΩ The amplifier, when unloaded, has an output resistance of Rout = 2.5 kΩ and an output voltage of Uout0 = 800 mV. 7.5 kΩ Rl = 600 mV = 800 mV ⋅ 2.5 kΩ + 75 kΩ Rout + Rl U out = U out 0 ⋅ 3 points 9.) Determine the voltage amplification of a basic common-source amplifier circuit Data: y21S = 5 mS, y22S = 25 µS, RD = 5 kΩ, Rl = 7.5 kΩ ⎛ 1 ⎞ ⎛ 1 ⎞ Aul = − y21S ⋅ ⎜⎜ × RD × Rt ⎟⎟ = −5 mS ⋅ ⎜⎜ × 5 kΩ × 7.5 kΩ ⎟⎟ = − 14 ⎝ 25 μS ⎠ ⎝ y22 S ⎠

4 points 10.) Draw a basic common-collector amplifier circuit Parts: 1 NPN transistor, 3 resistors, 2 electrolytic capacitors. +Ut In C1 Uin RB1 T C 2 RB2 RE Out Uout 4 points 11.) Write down the conjunctive serial number form of the logic function below ‘A’ is used to denote the variable of the highest place value. ( )( )( F4 = A + B + C + D ⋅ A + B + C + D ⋅ A + B + C + D ) F 4 = Π 4 (4, 9, 14) 3 points 12.) Write down the disjunctive normal form of the logic function below F4 = A ⋅ B ⋅ C + B ⋅ C ⋅ D + A ⋅ B ⋅ C ⋅ D F4 = A ⋅ B ⋅ C ⋅ D + A ⋅ B ⋅ C ⋅ D + A ⋅ B ⋅ C ⋅ D + A ⋅ B ⋅ C ⋅ D + A ⋅ B ⋅ C ⋅ D F4 = A ⋅ B ⋅ C ⋅ D + A ⋅ B ⋅ C ⋅ D + A ⋅ B ⋅ C ⋅ D + A ⋅ B ⋅ C ⋅ D írásbeli vizsga 1212 3/8 3 points 2012. május 25 Elektronikai alapismeretek angol nyelven középszint Javítási-értékelési útmutató Complex questions Maximum points: 60 Question 1 Maximum points: 15 a) b)

C = (C1 + C 2 ) × (C 3 + C 4 + C 5 ) C = (10 μF + 20 μF) × (10 μF + 20 μF + 30 μF) = 20 μF 4 points Q = C ⋅ U = 20 μF ⋅ 15 V = 300 μC 3 points U1 = U 2 = c) 300 μC Q = = 10 V C1 + C 2 10 μF + 20 μF U 3 = U 4 = U 5 = U − U 1 = 15 V − 10 V = 5 V 3 points τ = R ⋅ C = 100 kΩ ⋅ 20 μF = 2 s 2 points Question 2 a) c) Maximum points: 15 Z = R2 + (X C − X L ) = 2 I= b) 3 points (2 kΩ )2 + (4 kΩ − 2.5 Ω )2 = 2.5 kΩ 6V U = = 2.4 mA Z 2.5 kΩ 4 points 2 points U R = I ⋅ R = 2.4 mA ⋅ 2 kΩ = 48V 1 point U C = I ⋅ X C = 2.4 mA ⋅ 4 kΩ = 96V 1 point U L = I ⋅ X L = 2.4 mA ⋅ 25 kΩ = 6V 1 point L= XL 2.5 ⋅ 10 3 Ω = = 79.6 mH 2 ⋅ π ⋅ f 2 ⋅ π ⋅ 5 ⋅ 10 3 Hz 3 points C= 1 1 = = 7.96 nF 3 2 ⋅ π ⋅ f ⋅ X C 2 ⋅ π ⋅ 5 ⋅ 10 Hz ⋅ 4 ⋅ 103 Ω 3 points írásbeli vizsga 1212 4/8 2012. május 25 Elektronikai alapismeretek angol nyelven középszint Question 3 Javítási-értékelési útmutató

Maximum points: 15 a) Rin = R1 = 27 kΩ b) Au = 1+ 1 point R3 R2 R 3 = R 2 ⋅ (A u − 1) = 30 kΩ ⋅ (10 − 1) = 270 kΩ U in = U g ⋅ c) 4 points Rin 27 kΩ = 500 mV ⋅ = 422 mV Rg + Rin 5 kΩ + 27 kΩ U out = Au ⋅ U in = 10 ⋅ 422 mV = 4.22V 3 points 2 points 2 (4.22V ) = 89 mW U out = Rt 2 kΩ 2 Pout = fl = d) 2 points 1 1 = = 7.96 Hz 2 ⋅ π ⋅ Rt ⋅ C2 2 ⋅ π ⋅ 2 kΩ ⋅ 10 μF Question 4 Maximum points: 15 4 4 F =Π a) ( 0, 1, 2, 3, 6, 7, 10, 11,14, 15) 3 points C b) A 115 114 12 13 111 110 8 9 B ( F = C⋅ A + B 13 12 10 11 17 16 4 5 D c) D A 1 B 1 ) B 4 points 1 & F C d) 3 points 4 points F = C ⋅ (A + B) = C ⋅ (A + B) = C + A + B A 1 B 1 C 1 írásbeli vizsga 1212 1 1 F 4 points 5/8 2012. május 25 Elektronikai alapismeretek angol nyelven középszint Javítási-értékelési útmutató Evaluation Guidelines for the Written Examination You must use the centrally developed evaluation

guidelines for evaluating simple short questions and complex questions. When assigning points to solutions which include calculations (sizing), use the table below: • Quantitative aspects Qualitative aspects Elements Elements completeness of solution Proportion 70% • • • • Documentation of solution Proportion logic in the solution creativity accuracy use of measurement units Elements • • • 20% • Proportion neatness organisation use of standard symbols compliance with requirements in terms of engineering, format, and aesthetics 10% Therefore, you may assign maximum points to a solution only when it fully meets requirements not only in terms of quantitative aspects, but also in terms of qualitative aspects and the documentation of the solution. Scoring Simple Short Questions Question 1 (3 points) Correct completion 3 points. In case of one error 2 points, in case of two errors 1 point, in case of over two errors 0 point. When a cell is left empty,

consider it to be an error Question 2 (3 points) Formula 1 point, substitution 1 point, result 1 point. Question 3 (3 points) Formula 1 point, substitution 1 point, result 1 point. Question 4 (3 points) The score is equal to the number of correct answers. Question 5 (4 points) Formula 2 points, substitution 1 point, result 1 point. Question 6 (4 points) Formula 2 points, substitution 1 point, result 1 point. Question 7 (3 points) Correct completion 3 points. In case of one error 2 points, in case of two errors 1 point, in case of over two errors 0 point. When a cell is left empty, consider it to be an error Question 8 (3 points) Formula 1 point, substitution 1 point, result 1 point. Question 9 (4 points) Formula 2 points, substitution 1 point, result 1 point. írásbeli vizsga 1212 6/8 2012. május 25 Elektronikai alapismeretek angol nyelven középszint Javítási-értékelési útmutató Question 10 (4 points) Correct circuit 3 points, standard drawing symbols 1 point. No

points may be assigned to a circuit resulting in inoperability. Question 11 (3 points) Correct form 3 points. In case of one error 2 points, in case of over two errors zero point Question 12 (3 points) Correct form 3 points. In case of one incorrect term 2 points, in case of over one incorrect terms zero point. General Guidelines to the Quantitative Evaluation of Complex Questions You must accept (and assign the above specified points to) any solution which, though different from the evaluation guidelines, is technically correct. An examinee may receive maximum points for a question (task) only when he/she has properly substituted data in formulas and calculated the end result in this way. The use of the data in normal form must be required in justified cases. You may accept an end result with maximum points only when the amount and the measurement unit of the result are both fully correct. The smallest score you may assign to a task is 1 point, no fractional points are allowed. When

the tasks in a question are interrelated and the result of a task is incorrect and the incorrect result is used in subsequent task(s), then you must assign the above specified points to any correct solutions. Nevertheless, points must be deducted when: - the result of a task taken forward is clearly technically impossible or extreme, or - the result of a task used in a next one reduces the complexity of the subsequent task(s). Scoring Complex Questions Question 1 Maximum points: 15 a) For calculating C: formula 2 points, substitution 1 point, result 1 point. Maximum 4 points. b) For determining Q: formula 1 point, substitution 1 point, result 1 point. For determining U1 and U2: formula(s) 1 point, substitution(s) 1 point, result(s) 1 point. For determining U3, U4 and U5: formula(s) 1 point, substitution(s) 1 point, result(s) 1 point. Maximum 9 points. c) For determining τ: formula 1 point, substitution and result 1 point. Maximum 2 points. írásbeli vizsga 1212 7/8 2012. május

25 Elektronikai alapismeretek angol nyelven középszint Question 2 Javítási-értékelési útmutató Maximum points: 15 a) For determining Z: formula 2 points, substitution 1 point, result 1 point. For determining I: formula 1 point, substitution and result 1 point. Maximum 6 points. b) For determining UR 1 point. For determining UC 1 point For determining UL 1 point Maximum 3 points. c) For determining L: formula 1 point, substitution 1 point, result 1 point. For determining C: formula 1 point, substitution 1 point, result 1 point. Maximum 6 points. Question 3 Maximum points: 15 a) For determining Rin 1 point. Maximum 1 point. b) For calculating R3: formula 2 points, substitution 1 point, result 1 point. Maximum 4 points. c) For determining Uin: formula 1 point, substitution 1 point, result 1 point. For determining Uout: formula 1 point, substitution and result 1 point. For determining Pout: formula 1 point, substitution and result 1 point. Maximum 7 points. d) For

determining fl: formula 1 point, substitution 1 point, result 1 point. Maximum 3 points. Question 4 Maximum points: 15 a) Correct conjunctive serial number form 3 points. In case of one error 2 points, in case of two errors 1 point, in case of over two errors 0 point. Maximum 3 points. b) Correct simplification 4 points. You may assign maximum 2 points to a logically correct but less simple form. Maximum 4 points. c) Correct realization 4 points. You may assign maximum 2 points to a logically correct solution which includes more gates than specified above. Maximum 4 points. d) Correct realization 4 points. You may assign maximum 2 points to a logically correct solution which includes more gates than specified above. Deduct no points for the lack of transforming the algebraic form. Maximum 4 points. The above points are assigned to solutions for quantitative aspect only. The scores assigned in this way may be reduced to the extent as it is specified in the table above when the

qualitative aspects or the documentation requirements of the solution are not fully complied with. You may assign only the above specified points to answers contained in the present correction/evaluation guidelines. The scores specified above may be broken down only where it is expressly specified so. Scores assigned in this way may be integers only. írásbeli vizsga 1212 8/8 2012. május 25